Integrand size = 27, antiderivative size = 402 \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {2 b^3 \left (3 a^2-b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a \left (a^2-b^2\right )^{7/2} d}+\frac {b^3 \left (2 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a \left (a^2-b^2\right )^{7/2} d}+\frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))} \]
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Time = 0.40 (sec) , antiderivative size = 402, normalized size of antiderivative = 1.00, number of steps used = 19, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2976, 3855, 2727, 2743, 2833, 12, 2739, 632, 210} \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {2 b^3 \left (3 a^2-b^2\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a d \left (a^2-b^2\right )^{7/2}}+\frac {b^3 \left (2 a^2+b^2\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a d \left (a^2-b^2\right )^{7/2}}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 d \left (a^2-b^2\right )^3 (a+b \sin (c+d x))}+\frac {3 b^4 \cos (c+d x)}{2 d \left (a^2-b^2\right )^3 (a+b \sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a d \left (a^2-b^2\right )^2 (a+b \sin (c+d x))^2}+\frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {a \tan \left (\frac {1}{2} (c+d x)\right )+b}{\sqrt {a^2-b^2}}\right )}{a^3 d \left (a^2-b^2\right )^{7/2}}+\frac {\cos (c+d x)}{2 d (a+b)^3 (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 d (a-b)^3 (\sin (c+d x)+1)} \]
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Rule 12
Rule 210
Rule 632
Rule 2727
Rule 2739
Rule 2743
Rule 2833
Rule 2976
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\csc (c+d x)}{a^3}-\frac {1}{2 (a+b)^3 (-1+\sin (c+d x))}-\frac {1}{2 (a-b)^3 (1+\sin (c+d x))}-\frac {b^3}{a \left (-a^2+b^2\right ) (a+b \sin (c+d x))^3}+\frac {b^3 \left (3 a^2-b^2\right )}{a^2 \left (a^2-b^2\right )^2 (a+b \sin (c+d x))^2}+\frac {6 a^4 b^3-3 a^2 b^5+b^7}{a^3 \left (a^2-b^2\right )^3 (a+b \sin (c+d x))}\right ) \, dx \\ & = \frac {\int \csc (c+d x) \, dx}{a^3}-\frac {\int \frac {1}{1+\sin (c+d x)} \, dx}{2 (a-b)^3}-\frac {\int \frac {1}{-1+\sin (c+d x)} \, dx}{2 (a+b)^3}+\frac {b^3 \int \frac {1}{(a+b \sin (c+d x))^3} \, dx}{a \left (a^2-b^2\right )}+\frac {\left (b^3 \left (3 a^2-b^2\right )\right ) \int \frac {1}{(a+b \sin (c+d x))^2} \, dx}{a^2 \left (a^2-b^2\right )^2}+\frac {\left (b^3 \left (6 a^4-3 a^2 b^2+b^4\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a^3 \left (a^2-b^2\right )^3} \\ & = -\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}-\frac {b^3 \int \frac {-2 a+b \sin (c+d x)}{(a+b \sin (c+d x))^2} \, dx}{2 a \left (a^2-b^2\right )^2}+\frac {\left (b^3 \left (3 a^2-b^2\right )\right ) \int \frac {a}{a+b \sin (c+d x)} \, dx}{a^2 \left (a^2-b^2\right )^3}+\frac {\left (2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 \left (a^2-b^2\right )^3 d} \\ & = -\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^3 \int \frac {2 a^2+b^2}{a+b \sin (c+d x)} \, dx}{2 a \left (a^2-b^2\right )^3}+\frac {\left (b^3 \left (3 a^2-b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{a \left (a^2-b^2\right )^3}-\frac {\left (4 b^3 \left (6 a^4-3 a^2 b^2+b^4\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a^3 \left (a^2-b^2\right )^3 d} \\ & = \frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {\left (b^3 \left (2 a^2+b^2\right )\right ) \int \frac {1}{a+b \sin (c+d x)} \, dx}{2 a \left (a^2-b^2\right )^3}+\frac {\left (2 b^3 \left (3 a^2-b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a \left (a^2-b^2\right )^3 d} \\ & = \frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}-\frac {\left (4 b^3 \left (3 a^2-b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a \left (a^2-b^2\right )^3 d}+\frac {\left (b^3 \left (2 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {1}{2} (c+d x)\right )\right )}{a \left (a^2-b^2\right )^3 d} \\ & = \frac {2 b^3 \left (3 a^2-b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a \left (a^2-b^2\right )^{7/2} d}+\frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}-\frac {\left (2 b^3 \left (2 a^2+b^2\right )\right ) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {1}{2} (c+d x)\right )\right )}{a \left (a^2-b^2\right )^3 d} \\ & = \frac {2 b^3 \left (3 a^2-b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a \left (a^2-b^2\right )^{7/2} d}+\frac {b^3 \left (2 a^2+b^2\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a \left (a^2-b^2\right )^{7/2} d}+\frac {2 b^3 \left (6 a^4-3 a^2 b^2+b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2} d}-\frac {\text {arctanh}(\cos (c+d x))}{a^3 d}+\frac {\cos (c+d x)}{2 (a+b)^3 d (1-\sin (c+d x))}+\frac {\cos (c+d x)}{2 (a-b)^3 d (1+\sin (c+d x))}+\frac {b^4 \cos (c+d x)}{2 a \left (a^2-b^2\right )^2 d (a+b \sin (c+d x))^2}+\frac {3 b^4 \cos (c+d x)}{2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))}+\frac {b^4 \left (3 a^2-b^2\right ) \cos (c+d x)}{a^2 \left (a^2-b^2\right )^3 d (a+b \sin (c+d x))} \\ \end{align*}
Time = 5.85 (sec) , antiderivative size = 278, normalized size of antiderivative = 0.69 \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {\frac {2 b^3 \left (20 a^4-7 a^2 b^2+2 b^4\right ) \arctan \left (\frac {b+a \tan \left (\frac {1}{2} (c+d x)\right )}{\sqrt {a^2-b^2}}\right )}{a^3 \left (a^2-b^2\right )^{7/2}}-\frac {2 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}+\frac {2 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )\right )}{a^3}+\frac {2 \sin \left (\frac {1}{2} (c+d x)\right )}{(a+b)^3 \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )}-\frac {2 \sin \left (\frac {1}{2} (c+d x)\right )}{(a-b)^3 \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )}+\frac {b^4 \cos (c+d x)}{a (a-b)^2 (a+b)^2 (a+b \sin (c+d x))^2}+\frac {b^4 \left (9 a^2-2 b^2\right ) \cos (c+d x)}{a^2 (a-b)^3 (a+b)^3 (a+b \sin (c+d x))}}{2 d} \]
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Time = 2.59 (sec) , antiderivative size = 278, normalized size of antiderivative = 0.69
method | result | size |
derivativedivides | \(\frac {\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}+\frac {2 b^{3} \left (\frac {\left (\frac {11}{2} a^{3} b^{2}-2 a \,b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\frac {b \left (10 a^{4}+17 a^{2} b^{2}-6 b^{4}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}+\frac {a \,b^{2} \left (29 a^{2}-8 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}+\frac {a^{2} b \left (10 a^{2}-3 b^{2}\right )}{2}}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {\left (20 a^{4}-7 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{\left (a -b \right )^{3} \left (a +b \right )^{3} a^{3}}+\frac {1}{\left (a -b \right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}-\frac {1}{\left (a +b \right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}}{d}\) | \(278\) |
default | \(\frac {\frac {\ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{a^{3}}+\frac {2 b^{3} \left (\frac {\left (\frac {11}{2} a^{3} b^{2}-2 a \,b^{4}\right ) \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+\frac {b \left (10 a^{4}+17 a^{2} b^{2}-6 b^{4}\right ) \left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{2}+\frac {a \,b^{2} \left (29 a^{2}-8 b^{2}\right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{2}+\frac {a^{2} b \left (10 a^{2}-3 b^{2}\right )}{2}}{{\left (\left (\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) a +2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+a \right )}^{2}}+\frac {\left (20 a^{4}-7 a^{2} b^{2}+2 b^{4}\right ) \arctan \left (\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}}\right )}{\left (a -b \right )^{3} \left (a +b \right )^{3} a^{3}}+\frac {1}{\left (a -b \right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}-\frac {1}{\left (a +b \right )^{3} \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}}{d}\) | \(278\) |
risch | \(\frac {6 i a^{4} b^{3}-16 i a^{6} b \,{\mathrm e}^{2 i \left (d x +c \right )}+2 i b^{7} {\mathrm e}^{4 i \left (d x +c \right )}+11 i a^{2} b^{5}-2 a^{5} {\mathrm e}^{5 i \left (d x +c \right )} b^{2}-14 a^{3} b^{4} {\mathrm e}^{5 i \left (d x +c \right )}+a \,b^{6} {\mathrm e}^{5 i \left (d x +c \right )}-36 i a^{4} b^{3} {\mathrm e}^{4 i \left (d x +c \right )}-8 i a^{6} {\mathrm e}^{4 i \left (d x +c \right )} b +8 a^{7} {\mathrm e}^{3 i \left (d x +c \right )}+4 a^{5} b^{2} {\mathrm e}^{3 i \left (d x +c \right )}+24 a^{3} b^{4} {\mathrm e}^{3 i \left (d x +c \right )}-6 a \,b^{6} {\mathrm e}^{3 i \left (d x +c \right )}-2 i b^{7}-14 i a^{4} b^{3} {\mathrm e}^{2 i \left (d x +c \right )}-3 i a^{2} b^{5} {\mathrm e}^{4 i \left (d x +c \right )}+22 a^{5} b^{2} {\mathrm e}^{i \left (d x +c \right )}+30 a^{3} b^{4} {\mathrm e}^{i \left (d x +c \right )}-7 a \,b^{6} {\mathrm e}^{i \left (d x +c \right )}}{\left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) \left (-i b \,{\mathrm e}^{2 i \left (d x +c \right )}+i b +2 a \,{\mathrm e}^{i \left (d x +c \right )}\right )^{2} a^{2} d \left (a^{2}-b^{2}\right )^{3}}+\frac {10 i b^{3} a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d}-\frac {7 i b^{5} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d a}+\frac {i b^{7} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d \,a^{3}}-\frac {10 i b^{3} a \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d}+\frac {7 i b^{5} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{2 \sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d a}-\frac {i b^{7} \ln \left ({\mathrm e}^{i \left (d x +c \right )}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{b \sqrt {a^{2}-b^{2}}}\right )}{\sqrt {a^{2}-b^{2}}\, \left (a +b \right )^{3} \left (a -b \right )^{3} d \,a^{3}}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-1\right )}{d \,a^{3}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}{d \,a^{3}}\) | \(896\) |
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Leaf count of result is larger than twice the leaf count of optimal. 768 vs. \(2 (377) = 754\).
Time = 1.80 (sec) , antiderivative size = 1623, normalized size of antiderivative = 4.04 \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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\[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\int \frac {\csc {\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )}}{\left (a + b \sin {\left (c + d x \right )}\right )^{3}}\, dx \]
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Exception generated. \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.40 (sec) , antiderivative size = 411, normalized size of antiderivative = 1.02 \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\frac {\frac {{\left (20 \, a^{4} b^{3} - 7 \, a^{2} b^{5} + 2 \, b^{7}\right )} {\left (\pi \left \lfloor \frac {d x + c}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )}}{{\left (a^{9} - 3 \, a^{7} b^{2} + 3 \, a^{5} b^{4} - a^{3} b^{6}\right )} \sqrt {a^{2} - b^{2}}} + \frac {2 \, {\left (3 \, a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - a^{3} - 3 \, a b^{2}\right )}}{{\left (a^{6} - 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )} {\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}} + \frac {11 \, a^{3} b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, a b^{7} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 10 \, a^{4} b^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 17 \, a^{2} b^{6} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 6 \, b^{8} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 29 \, a^{3} b^{5} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 8 \, a b^{7} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 10 \, a^{4} b^{4} - 3 \, a^{2} b^{6}}{{\left (a^{9} - 3 \, a^{7} b^{2} + 3 \, a^{5} b^{4} - a^{3} b^{6}\right )} {\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + a\right )}^{2}} + \frac {\log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right )}{a^{3}}}{d} \]
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Time = 17.19 (sec) , antiderivative size = 2999, normalized size of antiderivative = 7.46 \[ \int \frac {\csc (c+d x) \sec ^2(c+d x)}{(a+b \sin (c+d x))^3} \, dx=\text {Too large to display} \]
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